Given: x2+1x2=7. Adding 2 on both the sides, we get,. ⇒x2+1x2+2=7+2. ⇒x2+1x2+2×x×1x=9. ⇒(x+1x)2=32. ⇒x+1x=±3. ∴x+1x=3. Cubing both the sides, we get,. ⇒(x+1x)3= ... |
Ifx2+1/x2−7 find the valve of x3+1/33. Given equation is x2+1/x2=7. we know that(x+1/x)2=x2+2.x.1/x+(1/x)2. =x2+2+1/x2. =(x2+1/x2)+2. =7+2. =9. ∴(x+1/x)2=9. ⇒(x ... |
5 авг. 2023 г. · Given x² + 1/x² = 7 —————(1) Adding 2 to both sides we get x² + 1/x² + 2 = 7 + 2 => (x)² + 2. x . 1/x + (1/x)² = 9 => (x + 1/x)² = (±3)² ... |
7 авг. 2024 г. · To find the value of x3+1x3 given that x2+1x2=7, we can follow these steps: Step 1: Start with the given equation. We have: x2+1x2=7. |
Solution: (x + 1/x)2 = x2 + 1/x2 + 2 given x2+1/x2=7 then (x + 1/x)2 = 9 x + 1/x = 3 now (x + 1/x |
If x2+1x2=7, find the value of x3+1x3, taking only the positive value of x+1x. View Solution. Q2. |
6 мар. 2022 г. · Originally Answered: If x^2+1/x^2=7, then what is x^3+1/x^3? ·. Given that. x^2+1/x^2 = 7. (x+1/x)^2 =x^2+1/x^2+2. = 7+2 =9. Therefore. (x+1/x)= ... |
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