8 мар. 2015 г. · Then (π√2)2=π22 would be algebraic, but this would mean π2 is algebraic, which is a contradiction since π is transcendental.

29 дек. 2017 г. · Hermite shows π2 is irrational by a method that avoids the use of continued fractions --- a method that very soon afterwards led to his proof ...

22 нояб. 2020 г. · π2n+aπn+b=β⇒β−b=πn(πn+a). I can't proceed, because the product of two transcendental isn't necessarily transcendental. How can I proceed ...

6 мая 2013 г. · I'm trying to use the fact that π is transcendental to show that √ π is also transcendental over Q. I don't know any theorems about algebraic and non- ...

27 авг. 2013 г. · Hermite's proof (en.wikipedia.org/wiki/Proof_that_%CF%80_is_irrational) shows that π2 is irrational. Yes, I know this isn't what you want.

9 сент. 2018 г. · We want to prove that α:= √ π + √ 2 ∈C is trancendental over Q. Attempt. We use proof by contradiction and so assume that α∈C is algebraic over Q.

13 нояб. 2013 г. · According to Wikipedia, most sums, products, powers, etc., of π have unknown status; in particular, it isn't known whether π √ 2 is transcendental.

30 нояб. 2019 г. · So if π can also be represented as a root of algebraic equation then why π is transcendental . pi · transcendental-numbers · Share.

16 июн. 2022 г. · First, we have to assume you already know that π is transcendental over Q, because that's a difficult proof that can't be done using purely ...

8 апр. 2011 г. · Does anyone has a link to a site that confirms that π is a transcendental number? Or, can anyone show how to prove that π is a transcendental ...