1 сент. 2015 г. · The most efficient way is to extract the ID from the path, then attempt to find it in the Set, making each filter execute in constant time. |
21 окт. 2021 г. · It can be done simply by using removeAll() method. You have to implement hashcode and equals in Car class. Then you can cars1.removeAll(cars2);. |
29 февр. 2016 г. · Given a list of elements, I want to get the element with a given property and remove it from the list. The best solution I found is: |
27 февр. 2018 г. · I have a requirement to subtract/remove POJOs in one list based on certain criteria (from another list) and show it on UI. |
2 июн. 2013 г. · You can use the removeAll method to remove the items of one list from another list. To obtain the duplicates you can use the retainAll method. |
1 дек. 2020 г. · The answer to your question is: impossible - you can't remove anything from a List obtained by invoking Arrays.asList. |
3 апр. 2022 г. · You can achieve that with Java 8 method Collection.removeIf() that expects a Predicate and will remove every element from the source that ... |
14 мар. 2018 г. · Note that Arrays.asList() creates an immutable list. If you create a regular ArrayList , you can just do list.removeAll(otherList); . |
28 февр. 2018 г. · Java 8 introduces a new method available for Collection types: removeif(). It accepts a predicate which defines the condition on which the elements should be ... |
21 авг. 2019 г. · Want to delete some elements from a list that is existed in another list · You can use listA.removeAll(listB) . That should be the fastest way. |
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