9 июн. 2010 г. · I'm not sure I understand your intent perfectly, but perhaps the following would be close to what you want: select n1.name, n1.author_id, ...

26 февр. 2018 г. · You could create a derived table (All_Status below) of all status (0 to 4) and cross join that to your svc_sms then left join to svc_sms_msg.

6 апр. 2021 г. · I am trying to build a query that will show me all equipment records, if it is currently in contract with the start/end date, and a count of any maintenance ...

29 авг. 2018 г. · I think something wrong in your select statement. SELECT publi.date, publi.mess, publi, publi.profil, publi.color, publi.name, publi.search ...

3 июл. 2022 г. · I'm struggling to get query for 2) and then join everything with query from 1) to get the result. Any help I would appreciate!

14 дек. 2022 г. · SELECT c.first_name, c.last_name FROM customer c INNER JOIN payment p ON C.CUSTOMER_ID = p.customer_id WHERE p.amount > (SELECT AVG(amount) FROM payment)

22 окт. 2015 г. · It generally won't make any difference, because they should result in the same query plan. At least, an EXISTS subquery will; ...

16 янв. 2010 г. · You will need to use one of the aggregate functions to select a single contact_id for each distinct phone number.

21 июл. 2023 г. · I want to know how I can get the same result using a subquery instead of using inner join on PostgreSQL?

20 янв. 2021 г. · I need to JOIN a table inside a correlated subquery. However, the chosen query plan of postgres is very slow. How can I optimize the following query?