12 окт. 2023 г. · The limit as x approaches infinity is infinite. To see this, write the limit as L = (exp(x)-1)/x = exp(x)/x - 1/x. |
![What is the limit of [1/x] as x approaches 0? - Quora](img.php?q=tbn:ANd9GcQUMb-W-w6joJCTp81LHHI-9OsCjgxRZ7MFgxH_WA3LEvlzIeiGTI7Dj7Y&s)
![How to find [math]\lim_{x\to \infty} e^{-x} \sqrt{x}[/math ...](img.php?q=tbn:ANd9GcRaf129qyhDengxWgbKDYqTMxeSKcppVfU-fTtCmAahMNFpyTfNvlldiLWG&s)
25 янв. 2024 г. · The limit as x approaches infinity is infinite. To see this, write the limit as. L = (exp(x)-1)/x = exp(x)/x - 1/x. |
19 февр. 2023 г. · To prove that lim (x→0) [(e^x-1) /x] =1, we can use L'Hôpital's rule, which states that for a limit of the form 0/0 or ∞/∞, the limit can be ... |
29 сент. 2023 г. · Clearly, the exponentials tend to zero as x↓0 x ↓ 0 , so it is risk free to plug these values in, giving the limit the value 1 1 . Now, suppose ... |
14 авг. 2023 г. · Given an epsilon \epsilon, find an x such that e^x > 1/eps. This will be true whenever x > ln(1/eps). Then subtract the expression whose ... |
20 дек. 2022 г. · Let L L denote the value of the given limit. Since this limit has the indeterminate form 0⋅∞ 0 ⋅ ∞ , we rewrite the limiting expression as a ... |
5 окт. 2023 г. · When x tends to infinity, e^(1/x) approaches 1. We can see this through the limit definition of e^(1/x) as x approaches infinity. |
31 мар. 2024 г. · We are given the limit. L=limx→∞(ln(1+ex)−x). L = lim x → ∞ ( ln ( 1 + e x ) − x ) . As written this is an indeterminate form of the type ... |
8 июл. 2017 г. · If limit is assumed to be correct (x tends to '0'), the answer will simply be (-∞)^(-1/e)= -∞. However, if x is tending to 'e', then comes the ... |
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