12 окт. 2023 г. · The limit as x approaches infinity is infinite. To see this, write the limit as L = (exp(x)-1)/x = exp(x)/x - 1/x.

29 сент. 2023 г. · Clearly, the exponentials tend to zero as x↓0 x ↓ 0 , so it is risk free to plug these values in, giving the limit the value 1 1 .

7 окт. 2023 г. · So the limit as x approaches 0 exists and equals 1 because they both approach the same thing.

3 апр. 2023 г. · The limit =0. By definition, if the limit at x->x0 exists, the left limit must be equal to the right limit (x->x0+ = x->x0-).

26 мар. 2021 г. · So the limit as x approaches 0 exists and equals 1 because they both approach the same thing.

8 февр. 2018 г. · What is limit of x tends to 0? = lim(h→0){e^(1/h)/-h} =-∞ x ∞ which is undefined. Therefore, RHL ≉ LHL . Hence limit does not exist .

17 окт. 2019 г. · The limit =0. By definition, if the limit at x->x0 exists, the left limit must be equal to the right limit (x->x0+ = x->x0-).

7 янв. 2023 г. · (2) e^x goes less than 1 when x goes negative, and gets closer and closer to zero as x goes more negative, but it is still always positive.

13 сент. 2021 г. · As you can see, any number except for 0 in this equation will output, 1, so the limit is 1. This is because as x gets closer and closer to 0, ...

8 июл. 2017 г. · X tends to 0. If limit is assumed to be correct (x tends to '0'), the answer will simply be (-∞)^(-1/e)= -∞. However, if x is tending to 'e', ...