9 янв. 2020 г. · In the 1 T plot of chemical process having Δ S ∘ > 0 and Δ H ∘ < 0 the slope is proportional to (where K is equilibrium constant) |
For determination of ∆ H # and ∆ S # a plot of ln ( k/T ) Vs 1/T (Figure 4) gives a slope = - ∆ H # /R and intercept = ( R/Nh ) + ∆ S # /R. Since ( R/Nh ) ... |
12 июл. 2023 г. · 11 is known as the van't Hoff equation. It shows that a plot of lnK vs. 1/T should be a line with slope −ΔrHo/R and intercept ΔrSo/R. Exercise 19.7.3 · Temperature Dependence of... |
Fig. 6 is a plot of ln k against 1/T; the regression of the plot allowed the activation energy and the Arrhenius constant to be calculated. |
The slope of a line in the graph of log k versus 1T for a reaction is −5841K. Calculate energy of activation for the reaction. View Solution. |
21 окт. 2023 г. · Does it make any sense to graph 1/T versus ln(Kc)? · 1. Note this equation Delta G =-RTln(K) is wrong. It should be ΔG∘=−RTln(K). · How do you ... |
Hint: The graph describes the equilibrium constant and temperature. The equation can be used to find out the slope. The slope value gives the enthalpy value ... |
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