Binding energy is given by. Eb=Δm.c2. For deuterium, Δm=0.0024u ⇒Eb=(0.0024×931MeVc2)c2=2.2344MeV =2.2344×1.6×10−13J ∴Eb=3.58×10−13J · ∴ · = · 3.58 · × · 10 · J.

25 июн. 2019 г. · In the case of deuterium, the mass defect is 0.002388 amu, which corresponds to a nuclear binding energy of 2.22 MeV for the deuterium nucleus.

9 янв. 2020 г. · Binding energy of deuterium is 2.23 MeV, then its mass defect in a.m.u. is. −0.0024; −0.0012; 0.0012; 0.0024.

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Опубликовано: 12 дек. 2023 г.

If the binding energy of deuterium is 2.23 MeV, then the mass defect in amu is?A. 0.0024 MeVB. 0.0048 MeVC. 0.0036 MeVD. 0.0012 MeV.

The mass defect of deuterium is 0.002amu. Find its binding energy in joules.Solution in Odia.

The difference between the mass of the atom and the sum of the masses of its parts is called the mass defect (Δm).

4 сент. 2024 г. · Binding Energy (B) = Δm × 931 MeV Where Δm = mass defect. CALCULATION: Given - Binding Energy (B) = 2.23 MeV The mass defect in amu is ⇒ B = Δm ×

29 июл. 2022 г. · B.E. of a nucleon =Δm×931.5Mev where Δm→ mass defect =? B.E. → Binding energy= 2.23Mev 2.23=Δm×931.5 ∴Δm=931.52.23​=0.00239≈0.0024amu.