22 сент. 2012 г. · x1/2=−b±√b2−4ac2a. Here, the degree of f is given to be 2. However, I was wondering on how to generalize this problem. For example, consider ...

22 февр. 2014 г. · For any set of n+1 points (xi,yi) with xi≠xj for i≠j, there is a unique polynomial f of degree at most n such that f(xi)=yi for all i. If you're ...

17 июн. 2014 г. · What's true is that through n+1 points there is unique polynomial of degree ≤n. For example every polynomial p of degree ≤n conincides with it's ...

9 мая 2016 г. · As there seems to be some confusion about what a polynomial is... An example of a polynomial (of degree N) in x is p(x)=N∑k=0ckxk.

22 окт. 2016 г. · ... Example: The vertices of f(x)=(x-5)^4-2(x-5)^2 are (4, -1), (5, 0) ... Finding an nth degree polynomial. 5 · Conditions for a unique root ...

8 мар. 2011 г. · A polynomial of degree at most n with more than n roots vanishes identically. Proof: By induction. The base case is n=0, which is obvious.

7 февр. 2018 г. · The roots of the polynomial x(x+1)(x+2)…(x+n) are the numbers 0,−1,−2…,−n. Therefore by Vieta's theorem you can expand. x(x+1)(x+2)…

8 сент. 2019 г. · In the case of a degree-26 polynomial and the coefficient of a14, it is given by the symmetric polynomial of degree 26−14=12 in −a,−b,…,−z, ...

12 июл. 2016 г. · It is actually possible for a polynomial of degree n to have more than n roots. For example, consider the ring R=Z/25Z. Consider the polynomial ...

18 дек. 2015 г. · The discriminant of an n'th degree polynomial is Δ=a2n−2n∏i<j(ri−rj)2, where an is the leading coefficient and r1,r2,…,rn are the roots. ...