4 дек. 2022 г. · The nth degree polynomial function with real coefficients satisfying the given condition? The given function value n=4;-1,5,and 4+3i are zeros; f(1) =-144.

9 окт. 2017 г. · Sure there is: X=3√17 X = 17 3 . This is a simple radical expression for the unique real root of this polynomial equation (the other roots are ...

25 февр. 2020 г. · Since the coefficients are real, if 4i is a root, so is -4i so the polynomial can be of the form f(x) = A(x - 2)(x - 4i)(x + 4i) You can ...

1 окт. 2017 г. · While I was in high school, I discovered an algorithm to find the approximat positive real root of any nth degree polynomial (if it exist).

24 сент. 2018 г. · In Introductory Algebra we are taught that one of the simple ways to solve a 4-term polynomial is through factoring by grouping.

18 апр. 2020 г. · How do I find an​ nth-degree polynomial function with real coefficients satisfying the given conditions: n=4; I and 2i are zeroes; f(-2) =40?

14 окт. 2020 г. · How do I find the nth-degree polynomial function with real coefficients satisfying the given conditions: n = 3; 2 and 4i are zeros; f (1) = -34?

26 апр. 2017 г. · In your example, you need to find the 3rd degree polynomial, so the answer would be 1+x+x^2+x^3, because the highest degree is 3. The confusion ...

23 мая 2023 г. · Because of the Fundamental Theorem of Algebra, every polynomial over R (or even over C), splits completely over C. · (x-c)(x-c`) = x²-(c+c`)x+c.c ...

21 июл. 2023 г. · How do I find an​ nth-degree polynomial function with real coefficients satisfying the given conditions: n=4; I and 4i are zeros; f(-1) =102? If ...