8 сент. 2015 г. · I think you should be able to use the name attribute: temp_dataframe.groupby(level=0,axis=0).apply(lambda x: foo(x.name, x)).

20 июн. 2019 г. · I am working with a dataset df_cities containing the following columns: city_name, country_name, population, language.

25 нояб. 2021 г. · I used group by for column class and want to use the value of class in x df.groupby('class').apply(lambda x: ??) pandas · dataframe · lambda.

19 мая 2022 г. · Use: df1 = df.groupby('score').agg(score_age = ('age', lambda x: x.name + x.sum())) print (df1) score_age score 2 42 3 48.

28 февр. 2017 г. · I'm looking for a way to get a list of all the keys in a GroupBy object, but I can't seem to find one via the docs nor through Google. There is ...

4 мар. 2015 г. · By doing groupby() pandas returns you a dict of grouped DFs. You can easily get the key list of this dict by python built in function keys() .

6 февр. 2013 г. · 6 Answers 6 · create groupby object based on some_key column · pick N dataframes and grab their indices · grab the groups · optionally - turn it all ...

17 янв. 2018 г. · There's probably no intelligent way for groupby.apply to do that other than drop the group variable in apply : df.groupby('A').apply(lambda ...

16 сент. 2022 г. · Try as follows: # wrap groupby object in `list`, then in `dict` groups = dict(list(dat.groupby('name'))) # all keys print(groups.keys()) ...

1 сент. 2019 г. · Each time f receives a sub-group the variable n is incremented. In your sample, you only have 5 different teams so a total of 5 groups passed ...