2 мар. 2022 г. · 1) Check data type of the index, is it string or is it integer? 2) Key error can be your key is not in the index.

20 авг. 2013 г. · This solution only works if your series has a sequential integer index. If your series index is by datetime, this doesn't work.

14 февр. 2022 г. · I have a 2-d array of an index of a pandas series. Would like to create a 2-d array of the values from the pandas series that correspond to the index.

7 дек. 2021 г. · You can use [].index to get the index of a value in a series. s = pd.Series(["koala", "dog", "chameleon"]) s[s == 'dog'].index

20 окт. 2019 г. · You can use boolean indexing based on the absence of an index in your list: yields[~yields.index.isin([1, 3, 5])].

29 мая 2020 г. · Simply use Series.reset_index and Series.to_frame : df = speed_tf.reset_index(drop=True).to_frame() Result: # print(df) Speed 0 -24.4 1 -12.2 2 -12.2 3

22 мая 2020 г. · Compare the dataframe to the filtered value, squeeze it to get a boolean array, and index the index to get your values.

4 сент. 2018 г. · I have a pandas series with boolean entries. I would like to get a list of indices where the values are True . For example the input pd.Series([ ...

12 июн. 2019 г. · But this is panda core series series and I just want to have "+5:30". How do I become this? Or is there another way instead of df.loc[...] to ...

17 февр. 2022 г. · Suppose I have a pandas series: a = [1 ,2 ,4 ,2 ,7 , 2 ,8] How to tell Python to return the indices that have values equals to 2?