8 дек. 2021 г. · Does anyone know how to unnest the array in Table A in such a way that I can then use all the items to join A & B with records for every item of every order?

6 янв. 2012 г. · I want the original position of each element in the source string. I've tried with window functions ( row_number() , rank() etc.) but I always get 1.

8 янв. 2015 г. · 2 Answers 2 · Parallel unnest() and sort order in PostgreSQL · Is there something like a zip() function in PostgreSQL that combines two arrays?

12 янв. 2022 г. · use the unnest() function in the from clause, then you can add the with ordinality option which returns the array index select t.id, u.name, ...

2 мар. 2013 г. · This returns a row with NULL in value for an empty array as well as for a NULL array, because only an array with elements in it produces TRUE in the test ...

15 авг. 2023 г. · Try using a lateral join like this: WITH cte AS ( SELECT type, array_agg(foo) AS foos, array_agg(bar) AS bars FROM the_table group by type ) ...

8 мая 2020 г. · I'm trying to unpack an array where each item has multiple elements, and can't seem to get the syntax right. I'm hoping that someone can point out what I'm ...

11 авг. 2020 г. · A single select will do it for you, but t and f will need to be true and false : select '58385', unnest(array[1,14,20,21,22,24,25,26,36,300 ...

22 июн. 2017 г. · Assuming current Postgres 9.6, your function would work like this: CREATE OR REPLACE FUNCTION pd.check(interval_ text[]) RETURNS void AS $func$

21 сент. 2022 г. · I need to create a SELECT query to replace an array with name_ids with an array of names like this: widget_id|names | ---------+-----------+ 1|{Ad,Bo,Che}| 2|{ ...