24 нояб. 2010 г. · "%f" is the (or at least one) correct format for a double. There is no format for a float, because if you attempt to pass a float to printf, it'll be promoted ... |
3 нояб. 2010 г. · printf and scanf function in C/C++ uses Microsoft C library and this library has no support for 10 byte long double. |
31 мар. 2014 г. · You can print as much digits after decimal point as you want with %.<num>f. eg; printf("i: %.15f \n", i); It prints 15 digits after decimal point. |
12 февр. 2019 г. · Passing the double to printf that is expecting an int presumably causes a cast to an integer and only looks at the bottom 4 bytes which are all 0 so 0 is ... |
3 июл. 2022 г. · The number you entered can't be represented exactly in a double . Typically, a double is represented using IEEE754 double precision format. |
30 сент. 2019 г. · My professor said that when you do scanf doubles are represented with %lf but in printf it's %f (which is for floats.) This is odd. |
23 янв. 2015 г. · I tried to printf long double float type on different computers including two Windows and one Mac but it turns out that none of them is working as I expected. |
30 мая 2013 г. · If your type is double: use printf("%.17g", number) . Do NOT use %f , since that only specifies how many significant digits after the decimal ... |
10 сент. 2020 г. · The printf() format %lf is for long double. The format %f is for double, and a float value is promoted to double when passed to printf(). |
1 сент. 2013 г. · Anyone knows if it is possible to use printf to print a VARIABLE number of digits? The following line of code prints exactly 2: printf("%.2lf", x); |
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