23 окт. 2013 г. · This should do the trick: a = np.array([1,2,3,4,5,1,6,1]) print np.where(a == a.min()). argmin doesn't return a list like you expect it to ... |
26 июл. 2019 г. · Approach #1. One approach based on array-assignment to setup a 2D array filled up NaNs , using those a values as column indices (so assumes ... |
5 мар. 2019 г. · You can just do this: # First index is all rows idx1 = np.arange(len(x)) # Second index is minimum values idx2 = np.argmin(m, ... |
28 мая 2021 г. · Redefine the indexes using np.r_ , then slice and zip the indexes in order to create intervals defining start and ending index of chunks, ... |
15 мар. 2019 г. · Use np.where to get all the indexes that match a given value: import numpy as np distance = np.array([2,3,2,5,4,7,6]) np.where(distance ... |
11 дек. 2015 г. · Use np.argpartition . It does not sort the entire array. It only guarantees that the kth element is in sorted position and all smaller ... |
1 апр. 2016 г. · Find index of min value in a matrix · Yes. I've tried: ij_min = RSS.argmin() and I got ij_min = 0, which isn't the right thing... · 1. RSS. · @ ... |
11 мар. 2019 г. · Use numpy argmin() : np.argmin(a, axis=1). where a is your numpy array. |
10 июл. 2017 г. · np.nonzero(theta) returns the index of the values that are non-zero. In your case, it returns,. [1,2,3]. Then, theta[np.nonzero(theta)] ... |
2 сент. 2013 г. · I have need the N minimum (index) values in a numpy array · 25 · Find the index of minimum values in given array in Python · 4 · Numpy: Get ... |
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