30 янв. 2011 г. · To check for the presence of 'abc' in any string in the list: xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456'] if any("abc" in s for

6 мар. 2021 г. · all() stops at the first item evaluates to False. Basically: if all(isinstance(x, (int, float)) for x in my_list): print("all numbers!") else: print("not all ...

17 июл. 2016 г. · I am doing a for loop of a list. Every single string, I want to .find, but instead of .find one item for a string, I want to check that string for anything in ...

3 апр. 2015 г. · I need to check whether a string contains any element of a list. I'm currently using this method: engWords = ["the", "a", "and", "of", "be", "that", "have", " ...

21 мая 2016 г. · Just use all() and check for types with isinstance(). >>> l = ["one", "two", 3] >>> all(isinstance(item, str) for item in l) False

28 авг. 2013 г. · Specification says to test for a list of strings, so checktype('bar') should return False. Good job using basestring.

29 апр. 2021 г. · I have two list (or string): one is big, and the other one is small. I want to check whether the bigger one (A) contains the small one (B) or not.

1 июл. 2020 г. · The overall check is False. What you want to do is check whether or not an element in the list is an instance of int, not whether or not they are equal to int.

25 апр. 2020 г. · I have a list of news titles and would like to check if any title contains any of the keywords in a list.

30 июн. 2011 г. · Use a generator together with any, which short-circuits on the first True: if any(ext in url_string for ext in extensionsToCheck): print(url_string)