9 июн. 2011 г. · index() will give the first occurrence of an item in a list. Is there a neat trick which returns all indices in a list for an element?

7 окт. 2008 г. · >>> ["foo", "bar", "baz"].index("bar") 1. See the documentation for the built-in .index() method of the list: list.index(x[, start[, end]]).

18 окт. 2018 г. · I have a list of strings, some of them are None. i want to get a new list of all the Indexes of None. list = ['a', 'b', None, 'c' ,None,

12 окт. 2017 г. · Use enumerate here >>> l = ['A','A','B','A','B','B','A'] >>> [i for i,d in enumerate(l) if d=='B'] [2, 4, 5]

1 июл. 2019 г. · I want the indexes of the unique values from the list in list format. So the output looks like: indexes=[0,1,3,4,5 ...

21 февр. 2018 г. · I want to essentially use one list ie. L = [10, 10, 100, 10, 17, 15] and using another list R = [10, 15] want to return N = [0, 1, 3,

3 июн. 2020 г. · I'm looking for a fast approach to find all the indexes in string which match with items (one or multiple words).

26 дек. 2021 г. · First you need to figure out which elements are repeated and where. I do it by indexing it in a dictionary. Then you need to extract all repeated values.

3 дек. 2017 г. · I'm trying to search an ArrayList for a user input. I've managed to create a search that prints the index of the first occurrence from within the list.

27 июл. 2022 г. · I am trying to find all the indices that have the same values in a list. but in my list, there are lists inside the list and I don't know how to do it.