19 окт. 2010 г. · You can simply use pathlib s glob 1 : import pathlib list(pathlib.Path('your_directory').glob('*.txt')) or in a loop:

8 февр. 2010 г. · I am trying to get a list of files in a directory using Python, but I do not want a list of ALL the files. What I essentially want is the ability to do ...

29 июл. 2022 г. · I want to search a specific directory for a file. And I want to search that file for a specific line that contains a specific string, and return only that line.

28 июн. 2021 г. · All you have to do is iterate over your dataframe's rows (where each row has a "mask" and "id" that correspond to one file), and then construct a filename from ...

13 нояб. 2020 г. · I want to list all files in a directory and subdirectories within that directory that match a file mask. For example "M:\SOURCE\*.doc"

13 февр. 2014 г. · Have you tried to use built-in functionality of GetFiles method? Directory.GetFiles(path, "Test 1*.xlsx").

2 февр. 2010 г. · I would like to list all files recursively in a directory. I currently have a directory structure like this: src/main.c; src/dir/file1.c ...

29 янв. 2014 г. · Well, the first problem is that you're passing file paths to a method which expects a directory. path1 = "c:\Client_Test.xlsx"; ...

5 мая 2011 г. · Piping find into grep is often more convenient; it gives you the full power of regular expressions for arbitrary wildcard matching.

22 апр. 2022 г. · I'm working on a music database. I want the user to define a mask to show the program how his folder structure is laid out for importing the music into the db.