24 февр. 2009 г. · locals() returns a dictionary with local names: def func(a, b, c): print(locals().keys()) prints the list of parameters.

3 мая 2009 г. · The simpliest way to wrap a function func(*args, **kwargs) is to manually write a wrapper that would call func() inside itself.

12 окт. 2011 г. · You should use the * operator, like foo(*values). Read the Python doc unpackaging argument lists. Also, do read this.

15 сент. 2014 г. · What is the pythonic way to enforce a function to take a specific set of values for a given parameter? For instance there is a function like:

3 нояб. 2022 г. · I would like to define a function make_function that returns a new function. It takes as arguments a list arg_names of argument names for the new function.

1 апр. 2015 г. · I'm trying to pass in a list of values to use as parameters. I tried using a list and a tuple but the function always returns zero. Has anyone got any advice?

29 мар. 2019 г. · Using a variable argument list might be nicer than requiring a list if your function is mostly going to be called with separate URLs.

9 янв. 2015 г. · I want to someway loop trough the arguments of the function, and if they are a string, convert them to a list with that single element.

21 июн. 2013 г. · I've found various detailed explanations on how to pass long lists of arguments into a function, but I still kinda doubt if that's proper way to do it.

12 нояб. 2018 г. · I have to write a simple function that takes variable number of arguments and prints the sum, something simple like(ignoring error checks):