24 февр. 2009 г. · locals() returns a dictionary with local names: def func(a, b, c): print(locals().keys()) prints the list of parameters.

24 янв. 2018 г. · You can use kwargs to print the arguments, and at the same time prevent the user from passing invalid keyword-arguments or arguments without a name.

20 окт. 2008 г. · In CPython, the number of arguments is a_method.func_code.co_argcount and their names are in the beginning of a_method.func_code.co_varnames.

9 февр. 2010 г. · Best, shortest answer: Use the inspect library with getfullargspec(function).annotations. Note that you have to explicitly typecast the function arguments.

11 апр. 2019 г. · Is there anyway I can programmatically get the descriptions for these arguments? Doesn't look it's possible but just making sure. Looks like ...

23 мая 2012 г. · I'm trying to work out how to, from within a function, get a completely populated *args and **kwargs, including the function's named parameters.

3 июл. 2021 г. · This can be accessed via the __annotations__ attribute of a function object for Python versions >= 3.0: type_annotation_dict = foo.__annotations__

29 мар. 2020 г. · I want to get the parameter names of a function while it is in a decorator function, I keep getting the function wrapper parameters that is inside the ...

2 янв. 2021 г. · Yes, you can use the inspect module to get information about the arguments passed to the function, or you can read all of the function's local variables from ...

26 мар. 2010 г. · You can use locals() to get a dict of the local variables in your function, like this: def foo(a, b, c): print locals() >>> foo(1, 2, 3) {'a': 1, 'c': 3, 'b': 2