18 сент. 2011 г. · I'm not sure I understand your question completely, but the easy solution is probably: >>> dict(items['fees'])['status'] 'pending'.

27 авг. 2014 г. · I need to get object with id=2. How can I select a proper object from this list, when I know only the value of the object attributes?

13 апр. 2011 г. · The task is to find an element in the main list based on a key that is any element of the inner list or tuple.

26 авг. 2013 г. · Is there a built-in/quick way to use a list of keys to a dictionary to get a list of corresponding items?

21 июл. 2016 г. · Try: yearslist = dictionary.keys() dividendlist = dictionary.values() For both keys and values: items = dictionary.items() Which can be used to split them as ...

1 сент. 2011 г. · Assuming every dict has a value key, you can write (assuming your list is named l ) [d['value'] for d in l]. If value might be missing, ...

24 янв. 2022 г. · You can iterate over match_keys and use dict.get to get the values under each key: out = [v for key in match_keys if key in locations for v in locations[key]]

20 мар. 2021 г. · I have dictionary like this my_dict={'0':['A','B','C'],'1':['D','E','F']} How can I access the key using one of the value if value is a list ?

26 мая 2013 г. · You can first transform your list of dictionaries into a single dictionary with "name" as the key: data = {x['name']: x for x in original_data}

7 июл. 2022 г. · I'm trying get the values from the below list by calling each of the keys: l=["'person': 'Male'", "'name': 'James Smith'", "'dob': 'Jul 20 1955'", "'car