9 мар. 2009 г. · How do I remove an element from a list by index? I found list.remove() , but this slowly scans the list for an item by value. python ...

7 апр. 2022 г. · Simply put, I just want an alternative to .pop that does not return the removed element and also takes an index for parameters.

28 июл. 2016 г. · x.pop(index) will remove the item at index. However, x = [x[i] for i in range(len(x)) if x[i] not in x[:i]] will remove the duplicates more quick

4 мая 2018 г. · I want to remove elements in details by index based on values from num. For example elements with index 3, 22, 23, 25, 28... (these are numbers from num list) ...

28 нояб. 2021 г. · Iterate the position list and remove the corresponding element at that position in the values list. This is my code in O(n**2). Any optimization is appreciated.

7 июн. 2016 г. · You can delete it by using keyword del. Here is the example. my_list = [1, 2, 3, 4, 5] del my_list[0] # 0 is the index This will delete the first index of my_ ...

25 июл. 2022 г. · You can try this if you want to delete the element by index value of the list: del letters[0][0] # [['b', 'c'], ['a', 'b', 'c']]

18 авг. 2015 г. · According to this answer, the complexity of these two methods is: pop O(n - i) remove O(n) with the list length n and index of the element i.

21 сент. 2017 г. · I want to iterate over the list and return a new nested list with each list returned with one value missing.

21 нояб. 2016 г. · The most functional (and Pythonic) way would be to create a new list, omitting the elements at those indices in the original list.