11 авг. 2013 г. · If I understood the question correctly, you can use the slicing notation to keep everything except the last item: record = record[:-1]. |
2 июн. 2019 г. · As per mentioned in the Python wiki. Time complexities are as follows: Pop last O(1); Delete Item O(n); Set Slice O(k+n). Experimental Study. |
13 апр. 2019 г. · .remove removes the first occurrence of an item. You could do something like del my_list[len(my_list) - 1]. Or simply: del my_list[-1]. |
7 апр. 2018 г. · The most efficient would be by iterating the list in reverse order, find the value 2, delete it and break the loop. |
15 дек. 2014 г. · Delete only the last element's last element, like this listadr = [['a', 'b'], [1, 2]] del listadr[-1][-1] print(listadr) # [['a', 'b'], [1]]. |
28 нояб. 2017 г. · If you want to remove the last elements you dont need to pass a parameter to pop. Just call a.pop() twice. |
29 окт. 2020 г. · I am trying to empty out list A by removing one element at a time starting from the end. I cannot seem to reduce the list to an empty one and I would like to ... |
20 авг. 2016 г. · I just simply want to remove all the elements in the python list one by one by remove() method, but find out that does not work. |
5 июл. 2012 г. · Assuming all your list items are strings with spaces as delimiters, here is how you can remove the first and last group of characters from each string in the ... |
30 мар. 2013 г. · If you wish to remove the last n elements, in other words, keep first len - n elements: lst = lst[:len(lst)-n] Note: This is not an in memory operation. |
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