3 июл. 2012 г. · You need to do this in a loop, there is no built-in operation to remove a number of indexes at once. Your example is actually a contiguous sequence of indexes.

9 янв. 2014 г. · You can remove them with a list comprehension, which will create a new list: >>> lst = [2, 5, 7, 12, 13] >>> [v for i, v in enumerate(lst) if i not in {4,3}] [2

27 окт. 2017 г. · moving multiple indexes using the pop function in python · You should have a look at collections.deque - smart container, implements rotation ...

14 окт. 2020 г. · You can use enumerate to iterate through your list, with corresponding indices. Then check those indices against your removal list.

16 июн. 2014 г. · I want to pop two items from the left (ie a and b ) and two items from the right (ie h , i ). I want the most concise an clean way to do this.

27 дек. 2020 г. · I have a list for indexes: indexes=[1,3,7] In the end, I want to remove 1st, 3rd and 7th element from the list and the output should be like:

30 нояб. 2018 г. · I would like to delete multiple items in a list by their index: dS = [0, 0.02, 0, 0.04, 0.07, 0] dN = [1, 0.02, 0.3, 0.7,

21 сент. 2022 г. · I want to remove elements from an original list tokens which are at specified indices indices_to_remove and also keep the record of the deleted records.

26 апр. 2014 г. · The best way is to reconstruct the string without the elements from the specific indexes and join them together.

16 авг. 2020 г. · Deleting multiple elements from a list, or less pythonic: result = [] for i, j in enumerate(a): if j not in index_list: result.add(i)