1 нояб. 2011 г. · It's a one-liner: list(set(source_list)) will do the trick. A set is something that can't possibly have duplicates.

29 дек. 2022 г. · You can use this method by converting the list into the set and then converting it into the list again. The set data structure contains only unique elements.

8 авг. 2020 г. · You could use itertools.groupby to solve it. groupby the key x[0] ie first element in the list and then take first value from the grouped values.

16 июн. 2022 г. · You can use a set to de-duplicate and then use index to get only the first occurrence from the word_type list.

29 июл. 2019 г. · I tried to remove duplicates from a list in Python 3 by converting it into a set by using set(). However I tried to achieve a certain order at the end of the ...

30 авг. 2015 г. · The best way is to convert your sets to frozenset s (which are hashable) and then use set to get only the unique sets, like this

4 окт. 2017 г. · I have a list of instances of a certain class. This list contains duplicates, in the sense that duplicates share the exact same attributes. I want to remove ...

20 нояб. 2011 г. · Convert to a set: a = set(a) Or optionally back to a list: a = list(set(a)) Note that this doesn't preserve order.

19 авг. 2016 г. · I need to go through them and remove all the duplicates inside each list (no need to compare between lists, only inside each one).

24 февр. 2012 г. · The strategy is to convert the list of dictionaries to a list of tuples where the tuples contain the items of the dictionary.