19 июн. 2015 г. · Use re.sub. Just match all the chars upto I then replace the matched chars with I. re.sub(r'^.*?I', 'I', stri) |
2 янв. 2017 г. · Suppose I have a string: 997 668, now I need to remove anything before space ie I need 668 as the output. I need a solution using regular expression. |
4 апр. 2021 г. · You can build a regex from the end mark of a line using the anchor $. Using your own description, use the regex: (\d\d\.[^.]*)\.[^.]*$ |
26 нояб. 2021 г. · Using str.replace : df["address"] = df["address"].str.replace(r'^[^,]*,\s*', ''). Here is a regex demo showing that the logic is working. |
5 авг. 2019 г. · I want to remove all the text before and including */ in a string. For example, consider: string = ''' something other things etc. */ extra text. ''' |
15 окт. 2015 г. · Say I have a string and I want to remove the rest of the string before or after certain characters are seen. |
15 апр. 2015 г. · The program I am currently working on retrieves URLs from a website and puts them into a list. What I want to get is the last section of the URL. |
1 нояб. 2020 г. · Here we find the first occurance of \x00 and then take everything to the end of the string as well using .* . The result is your string minus 'removethis'. |
30 июл. 2014 г. · python - Use Regex re. sub to remove everything before and including a specified word - Stack Overflow. |
26 июл. 2022 г. · How can i remove every character before a specific character in a tuple of lists of strings in Python ; 3. Better add the expected output, at ... |
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