14 июл. 2015 г. · A very annoying part about R is the inconsistency w.r.t. na.rm and its variants... – MichaelChirico. Commented Jul 14, 2015 at 18:02. 6. at ... |
2 мая 2022 г. · There is no na.rm argument in cor , it is use . According to ?cor , the usage is. cor(x, y = NULL, use = "everything", method = c("pearson", ... |
26 сент. 2010 г. · The 1 s are because everything is perfectly correlated with itself, and the NA s are because there are NA s in your variables. You will have to ... |
24 июл. 2021 г. · I'm trying to calculate the Pearson correlation for my data. So far I successfuly did it for daily and hourly returns, ... |
24 апр. 2014 г. · How to compute a running cor.test() in a data.frame with NA values in R? Ask Question. Asked 10 years, 6 months ago. Modified 10 years, 6 ... |
17 нояб. 2014 г. · There is no parameter named na.rm in function cor. You should substitute your code as: use = "complete.obs". |
5 апр. 2017 г. · I want to suppress the NAs such that R will ignore them and run the function anyway. I am reading that I can specify this with na.rm=TRUE, like: |
13 авг. 2015 г. · You can greatly simplify your code like this: cm = cor(mts.data, use = "p") cm[abs(cm) <= 0.2] = 0. which gives: > ... |
26 апр. 2020 г. · I'm comparing it to a column of 352x1 and there are a few NA's throughout, so I'm trying to figure out how to handle this and get the P value's ... |
25 янв. 2013 г. · The mean function to compute THE RMSE has an na.rm argument, You can use it like this : RMSE <- function (pred,obs,na.rm=FALSE){ ... |
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