24 апр. 2024 г. · The Rogers-Ramanujan continued fraction is defined by R(q)=q1/51+q1+q21+q3⋱.

16 янв. 2024 г. · This continued fraction also plays a starring role in the Ramanujan Machine's motivation of their recently discovered "conservative matrix field ...

9 июн. 2016 г. · Let R(q) be the Rogers-Ramanujan continued fraction R(q):=q1/51+q11+q21+q31+…,|q|<1. Let also for r>0 Y=Y(r):=R(e−2π√r)−5−11−R(e−2π√r)5.

17 окт. 2024 г. · Who solved the Bring quintic using the Rogers-Ramanujan continued fraction R(q) and how to find all five roots? · Who found this nice solution?

10 нояб. 2024 г. · The Rogers-Ramanujan continued fraction R(q) can solve the Bring quintic via a quartic. Surprisingly, so can Ramanujan's cubic continued ...

10 нояб. 2024 г. · It turns out Ramanujan's cubic continued fraction C(q) and x3+y3=1 can do so as well. Thus, all three Platonic symmetries (octahedral, ...

14 сент. 2010 г. · The angle θp has little arithmetic meaning compared to τ(p). Expressed in terms of τ(p), this identity is something like 1111/2/(√3(τ(11)−1111/2) ...

20 окт. 2013 г. · Why does the Rogers-Ramanujan continued fraction R(q) appear in Emma Lehmer's quintic? · I think it would be helpful for you to check Henri ...

5 окт. 2012 г. · The first three are by Ramanujan, the fourth is the Ramanujan-Gollnitz-Gordon cfrac, while the last is by Naika, et al (using an identity by Ramanujan).

is the generalized continued fraction of Ramanujan. Does anybody know any nice formula for H(x,q)+ ...