13 июн. 2018 г. · I'm trying to extract the text following deviceSerialNumber= that occurs until either a & or the end of the string.

26 июл. 2023 г. · You should be able to use REGEXP_SUBSTR function - Amazon Redshift, perhaps like this: SELECT regexp_substr(note_internal, '\[(.*)-', 1, 1, 'e')

17 сент. 2021 г. · How do I extract a certain value between two substrings in redshift with regex? I have strings like the one below in a column in redshift:

15 июл. 2019 г. · In Redshift, you can use split_part(): select split_part(split_part(col, ')', 1), '(', 2)::int as a, split_part(split_part(col, ')', 2), '('

19 мар. 2018 г. · Use regexp_replace(text,text,text) function to do so giving the pattern to match and replacement string.

17 июн. 2019 г. · In both Postgres and Redshift, you should be able to use regexp_replace() : select regexp_replace(str, '-[^-]+$', '')

3 дек. 2020 г. · You can extract a pattern using a subexpression: select regexp_substr(data, ',3=([^,]*)', 1, 1, 'e').

24 мая 2021 г. · Redshift Extract String Between Two Patterns (regexp_substr) · 1 ... How to get substring based on a character and starting to read the string ...

29 апр. 2020 г. · I think you can use regular expressions: regexp_substr(str, 'category:([^-])+', 1, 1, 'e').

6 авг. 2019 г. · You can use regexp_replace() instead: select regexp_replace(full_utm, '.*utm_source=(.*)&.