30 янв. 2015 г. · But Redshift does not support free-standing VALUES expressions (outside of INSERT commands). So, for a single row: SELECT * FROM (SELECT 1) AS q ...

20 сент. 2019 г. · The most efficient way to simulate a multi-row VALUES clause is to create an array-of-arrays for the rows and columns of the data, and then unpack it.

26 окт. 2020 г. · I have a large Redshift tables (hundreds of millions of ROWS with ~50 columns per row). There is a need for me to find rows that have duplicate columns for a ...

22 апр. 2020 г. · I have a situation where I want to show a value that corresponds to one field in a table but in all rows. What is better is to show you an example in a ...

13 окт. 2020 г. · I was able to resolve this using the following query : select id, start_date , end_date, listagg(col_name, ', ') as new_col from ( select id ...

9 февр. 2022 г. · I would like to filter from my table orders all zipcodes that start with the letters "B1", "NW1", "C13", etc. For example, postcodes in the UK can be "NW8 8AB".

19 нояб. 2022 г. · I'm trying to extrace data on the top 80% of a certain value. Say my dataset is I have select restaurant ,pizza ,sum(sold) over (partition by restaurant order ...

24 авг. 2023 г. · Redshift can't sort an array. You have to unnest, order it, then turn it back to an array and compare using something like a hash.

14 янв. 2020 г. · One way how to do this would be to create SQL which selects all text-like columns and generates another SQL.

7 апр. 2021 г. · Basically what I need is to have a string 'tag1' and see if it exists in the list 'tag1','tag2' or 'tag3'. This should give me 1 as there is a match.