Given a signed 32-bit integer x , return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, ...

15 февр. 2024 г. · Given a signed 32-bit integer x , return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer ...

class Solution { public: int reverse(int x) { long ans = 0; while (x != 0) { ans = ans * 10 + x % 10; x /= 10; } return (ans < INT_MIN || ans > INT_MAX) ?

26 окт. 2020 г. · This problem is pretty straightforward . To reverse an integer, we only have to make most significant digit as the least significant digit and ...

Can you solve this real interview question? Reverse Integer - Level up your coding skills and quickly land a job. This is the best place to expand your ...

21 мая 2023 г. · The reverse method takes an integer x as input and returns the reverse of that integer. It initializes a variable rev to 0, which will store the ...

14 мая 2022 г. · In the first code block, rev is an integer. Thus, it is impossible for it to be greater than Integer.MAX_VALUE - the maximum value for an ...

Продолжительность: 12:16
Опубликовано: 23 дек. 2022 г.

View undefined's solution of Reverse Integer on LeetCode, the world's largest programming community.

12 янв. 2014 г. · There has an easy way to solve the problem. Convert x to long, and check if the result >= Integer.MAX_VALUE, otherwise return 0.