12 янв. 2012 г. · A round function should take anything below x.5 and round it to x. Anything x.5 and upwards should round to x+1.

21 нояб. 2011 г. · The round() function rounds __x to the nearest integer, but rounds halfway cases away from zero (instead of to the nearest even integer).

9 дек. 2011 г. · If you want to round a float to the nearest whole number, just add 0.5 and cast to the appropriate integer type.

13 янв. 2020 г. · Just subtract 1 at the digit that should be rounded (in your case 0.01) and then use the standard rounding function.

11 июн. 2022 г. · I want to round a decimal number (x),but I need to do it differently depending on how it is. If it has integer significant digits, we round to the nearest ...

29 апр. 2021 г. · I need to do a sort of round, for example: 0.1 should become 0.0 0.2 => 0.0 0.3 => 0.5 0.4 => 0.5 0.5 => 0.5 0.6 => 0.5

27 июн. 2019 г. · I want to round any number a user inputs (ie. 12.12345) to a specific decimal place. For my circumstance, to the 3rd decimal place (ie.

26 апр. 2020 г. · To round a float variable up to the next whole number: float someFloat = 4.2; int roundedUp = ((int)someFloat) +1; Casting to int will always truncate the ...

22 февр. 2020 г. · The round() function rounds __x to the nearest integer, but rounds halfway cases away from zero (instead of to the nearest even integer). Overflow is ...

26 сент. 2021 г. · You can do a simple oled.print(unknownFloat, 1); to get a rounded float printed to the display with one decimal.