11 янв. 2012 г. · This will go through and find any lines that pass the aaa= test, which means that the line contains the letters aaa=. Then it replaces the entire line with aaa ... |
28 июн. 2012 г. · You can use the change command to replace the entire line, and the -i flag to make the changes in-place. For example, using GNU sed: |
9 авг. 2009 г. · Use this solution with GNU sed: sed ':a;N;$!ba;s/\n/ /g' file. This will read the whole file in a loop ( ':a;N;$!ba ), then replaces the newline(s) |
2 июл. 2009 г. · This works: sed -rne 's/(dbservername)\s+\w+/\1 yyy/gip'. (When you use the -r option, you don't have to escape the parens.). |
26 сент. 2014 г. · I'm trying to replace a single line in a file with a multiline string stored in a variable. I am able to get the correct result when printing to screen. |
24 июн. 2020 г. · The main trick is to use r command to add contents from the other file for the starting line address. And then delete the line(s) to be replaced. |
20 июл. 2016 г. · The first sed replaces the previous content in quotes in-place if m11111 appears on an even-numbered line; the second one repeats the process. |
8 мар. 2016 г. · This might work for you (GNU sed): sed 's/[^*~]\+/abc123/4' file Replace the fourth occurrence of something which is does not contain a ~ or a * with abc123. |
8 мая 2013 г. · You can use an expression sed '/match/s/.*/replacement/' file. This will perform the sed 's/match/replacement/' expression in those lines containing match. |
4 сент. 2013 г. · I'm trying to find a line in a file and replace the next line with a specific value. I tried sed, but it seems to not like the \n. How else can this be done? |
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