6 июн. 2009 г. · SelectMany flattens queries that return lists of lists. For example public class PhoneNumber { public string Number { get; set; } }

8 мар. 2021 г. · First step get a flat list of all DailyAttendances .SelectMany(x => x.DailyAttendances) Now transform those into AttendanceList.

28 июн. 2016 г. · You can access the parent inside the SelectMany at least in a two ways: (A) Use Select inside the SelectMany : parents.SelectMany(p => p.Childs.Select(c => new ...

4 янв. 2017 г. · I understand that if the collection is null, SelectMany returns null instead of an empty list. And then I am confused because we do a Distinct.ToList().

11 окт. 2013 г. · SelectMany in C# corresponds to bind in Haskell (>>=) or flatMap in Scala. The signature of >>= in Haskell is: (>>=) :: Monad m => m a -> (a ...

12 нояб. 2018 г. · You have to first flatten all the lists into a single list, which is what .SelectMany() does, and then you can do .Select() on it.

27 авг. 2019 г. · SelectMany is implemented as a yield return in a foreach loop, so you've already implemented it as a yield return on each combo; you've just hidden the yield ...

5 сент. 2016 г. · I am looking for an elegant solution to aggregate a child collection in a collection into one large collection. My issue is when certain child collections ...

4 мая 2015 г. · Put the index out of the SelectMany: List<string> animal = new List<string>() { "cat", "dog", "donkey" }; List<int> number = new List<int>() { 10, 20 };

21 июн. 2018 г. · You can extract a list of Player objects using SelectMany with some casting: var allPlayers = players .SelectMany(list => (List<object>)list) .Cast<Player>();