23 июл. 2015 г. · Result 2.12: If for every h>0 we have that |f(x+h)−f(x)| is unbounded on I, then f is not uniformly continuous on I. An example of a bounded, continuous function on - ( - 0, 1 Prove $f(x)$ is not uniformly continuous on $(0,1) Proving that $f(x) = \frac{1}{x}$ is not uniformly continuous over ... Другие результаты с сайта math.stackexchange.com

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Опубликовано: 11 июн. 2015 г.

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Опубликовано: 5 февр. 2021 г.

15 нояб. 2022 г. · I leave the continuity part to you. For the uniform continuity, let us assume that the function is uniformly continuous. Take ϵ=1/2.

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Опубликовано: 11 февр. 2021 г.

(b) Prove that the function f(x)=1/x2 is not uniformly continuous on (0,1]. (c) Prove that the function f(x) = x3 is not uniformly continuous on [0,+∞).

For example, if A = (0,1) and f(x)=1/x, then f is continuous on A, but it is not uniformly continuous on A. The point is that if x is close to zero, then δ ...

Since c ∈ (0, 1) was arbitrary, f is continuous on (0, 1). Proposition 3: The function f(x) = 1 x is not uniformly continuous on the interval (0, 1).

11 июн. 2015 г. · Proof that f(x) = 1/x is not Uniformly Continuous on (0,1). Video by The Math Sorcerer on youtube. Please Subscribe here, thank you!

2 авг. 2020 г. · Q: For the function y =1/x, why is it not uniformly continuous on the interval (0,1) but is uniformly continuous on [a,1) for all a ∈(0,1) ? I ...