split_part snowflake site:stackoverflow.com - Axtarish в Google
25 авг. 2023 г. · Since your input comes in a variety of forms, SPLIT_PART won't be sufficient. Using Snowflake's REGEXP_SUBSTR to handle all 3 scenarios ...
7 дек. 2022 г. · The result of the Split Part is used in the Copy Command for inserting records into a snowflake table.
30 нояб. 2021 г. · I am trying to use SPLIT_PART to retrieve value available after the symbols '.' or ':'. Example - data = 'first.middle.last' split_part(data,'.',-1)
15 окт. 2020 г. · To prove that there's no limit close to 256 bytes, I generated a 3MB string with 3 substrings. split_part() was able to extract a 1MB string ...
24 февр. 2020 г. · When I run the below query in the Snowflake the value for second_value is shown as blank instead of NULL Value. How I can get NULL value for this sample data.
8 авг. 2022 г. · I have records in a column, from which I need to extract the string (no need of numeric values) after last hyphen(-). I tried with SPLIT_PART in Snowflake.
21 мар. 2023 г. · I have a string from a csv file, delmited with '|' and I want to take this string, split it and make it into separate columns which will be used as the header ...
4 окт. 2022 г. · I want to split the column OWNERS at delimiter ',' and create new columns. No of columns to be created depends on owners in OWNERS column.
29 нояб. 2022 г. · Your string is a JSON string, so it may already be stored in Snowflake as a variant type. If it is not, you can convert it to a variant ...
11 февр. 2022 г. · I am new to snowflake and I am trying to run an sql query that splits values with delimiters( semi-column ) and create columns for each of them.
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