8 окт. 2012 г. · This helped me resolve how to do multiple counts and output them in a single SELECT statement with each count being a column.

15 янв. 2021 г. · You can do it with aggregation and window functions: SELECT DISTINCT SUM(MAX(CASE WHEN info = 'yes' THEN 1 ELSE 0 END)) OVER () id_as_yes, ...

2 мар. 2018 г. · I have a query is used to display information in a queue and part of that information is showing the amount of child entities (packages and labs) that belong ...

14 мар. 2017 г. · This may depend on what DBMS you're using, but most should support something like this: select datename(month, dtComplete) as Month ...

5 сент. 2013 г. · If you want to count students who got A in history, B in maths and E in Geography: select count(*) from Table1 where [History] = 'A' and [Maths] = 'B' and [ ...

27 сент. 2013 г. · I have these queries: SELECT COUNT(*) FROM t_table WHERE color = 'YELLOW'; SELECT COUNT(*) FROM t_table WHERE color = 'BLUE'; SELECT COUNT(*) FROM t_table

16 сент. 2014 г. · Use d2.id in your count function with distinct,so the repeated children for a department will be counted only once. SELECT d.

2 апр. 2011 г. · Using a CASE statement lets you count whatever you want in a single query: SELECT SUM(CASE WHEN Persons.Name = 'John' THEN 1 ELSE 0 END) AS JohnCount.

6 февр. 2013 г. · I was just wondering if there is any way to get two separate "count" totals from a table using one query?

16 мар. 2012 г. · I have a table and I need calculate two aggregate functions with different conditions in one statement. How can I do this?