24 мар. 2020 г. · Is this proof right? Let sqrt(2)^sqrt(2) be a rational number q/p, where p, q are all integers, p, q are nonzero, and the gcd of p, q is 1.

17 нояб. 2011 г. · So in either case, sqrt(2)sqrt(2) is rational or it is irrational, we were able to get two irrational numbers such that ab is rational.

21 сент. 2024 г. · Sqrt(2) is the same as 21/2. So your number is actually 2√2/2 which is also 21/√2. Since 1/√2 is clearly irrational, your question now is this: ...

13 февр. 2013 г. · So at least one of √2 or √2√2 is an irrational number which, raised to the √2th power (an irrational power), gives you a rational number!

14 нояб. 2014 г. · I know that 2a/b means the bth-root of 2a, but since square root of 2 is not rational, how could I imagine it? or could I simplify it somehow?

10 нояб. 2023 г. · In grade school, our teacher showed us a simple proof that sqrrt(2) is irrational: if a^2/b^2 = 2, then a must be divisible by 2. Substitute 2k ...

15 мая 2018 г. · According to Rolling Stone he thought it was two, and apparently has his own mathematical system for which I presume this construct is based on.

28 сент. 2023 г. · Since a fraction of two integers is by definition a rational number, this means that the square root of 2 is rational, which contradicts the ...

6 мая 2023 г. · But then we show a contradiction by showing that our fraction isn't actually simplified, and thus sqrt(2) cannot be rational. Note that a lot ...

14 мая 2024 г. · I was reading about proving sqrt of 2 is irrational and in the proof they say that gcd=1 where sqrt 2=p/q. How can we know it is 1?