5 сент. 2021 г. · Is range_value_t supposed to always give me a decayed type? The value_type of an iterator (and, consequently, a range) should always be a ...

19 нояб. 2022 г. · I want to write a function that makes a std::vector out of an arbitrary range. I'd like this function to have a nice, explicit declaration.

11 окт. 2022 г. · When you try to define a similar function but take the second argument away, C++ is no longer able to deduce the value type.

2 авг. 2024 г. · With class template argument deduction, it's possible. template< std::ranges::contiguous_range R, typename T = std::ranges::range_value_t<R> > ...

26 янв. 2021 г. · The problem here is: what is the actual constraint that you want? Do you want to: constrain on the range's value type being specifically T ...

18 июл. 2022 г. · I want to define a template function that accepts a range and a function of the element type. Something like so: template<std::ranges::range R, R::element_t T>

10 апр. 2024 г. · We get something like this: template<std::ranges::view ViewOfDetections> requires std::same_as<std::ranges::range_value_t<ViewOfDetections>, ...

1 июн. 2024 г. · I need the accessor function for DataWrapper to return a container of MyInterface* values (pointers because we are really returning Data values).

7 сент. 2021 г. · template <std::ranges::range Range> requires std::same_as<std::ranges::range_value_t<Range>, int> auto TransformIt(Range r) { return r | std

25 февр. 2023 г. · My solution is to simply check if each element is in error and then if there are no errors transform the result to the desired view.