11 авг. 2021 г. · string.Join() in the second case takes an array of arguments, which are separated by commas. You pass the first argument list.Select (t => t) , and the second ...

18 окт. 2012 г. · I'm trying to split a string into an array, take first element out (use it) and then join the rest of the array into a seperate string.

9 июл. 2013 г. · You could do this string finalString = String.Join(", ", myList.ToArray(), 0, myList.Count - 1) + ", and " + myList.LastOrDefault();

24 февр. 2017 г. · The problem with your current code is that it calls string.Join(string, params IEnumerable<object>) : it will treat list as an object, not a lis ...

27 апр. 2012 г. · I'd just concatenate each item, and use String.Concat to put them together: string num = String.Concat( Enumerable.Range(1, 10).Select(n => "[" + n + "]") );

7 мая 2013 г. · The problem is that when I call string.Join it returns the literal string "System.String[]" instead of the actual concatenated string.

14 июн. 2009 г. · It creates a string from an array, separating each element of array with a symbol given. But general - it doesn't add a separator after the last element!

10 мая 2012 г. · For a list of a simpler type, such as List<string> , I perform this simply as: String.Join("|", myList.ToArray()); . Is there a way I can do ...

16 авг. 2012 г. · Yes, you can use the overload of String.Join (new in .NET 4) which takes an IEnumerable<String> and a little bit of Linq.

21 дек. 2017 г. · I have a list with ID's. What I want to do is to return all the elements in a single string, and seperate them with ' #'.