Given, a polynomial x + 3 3 . We need to find the coefficient of x in the expansion of x + 3 3 . Using the formula, a + b 3 = a 3 + b 3 + 3 a 2 b + 3 a b 2

9 янв. 2020 г. · Using the formula, (a+b)3=a3+b3+3a2b+3ab2 (x+3)3=x3+27+9x2+27x. Therefore, coefficient of x is 27. Was this answer helpful? upvote 100.

So, the answer is D. flag.

6 янв. 2022 г. · (x + 3)3 = x3 + 27 + 9x2 + 27x. Therefore, the coefficient of x is 27. ✦ Try This: The coefficient of x in the expansion of (x + 2)3 is. Не найдено: 33 | Нужно включить: 33

9 янв. 2020 г. · The coefficient of x in the expansion of ( x + 3 ) 3 is: (a) 1 (b) 9 (c) 18 (d) 27 3. Zero of the polymemial. Open in App Open_in_app.

12 сент. 2021 г. · So, coefficient of x^33 in the expansion if the given binomial expression is zero .

14 сент. 2021 г. · The binomial expansion formula gives this coefficient as (10 choose 3). That is, the coefficient must be 10!/(7!)(3!) = 10 x 9 x 8 / (3 x 2) = ...

3 февр. 2021 г. · The coefficient of x in the expansion of (x+3)3is · The correct Answer is:D · Now, (x+3)3=x3+33+3x(3)(x+3) [using identity ,(a+b)3=a3+b3+3ab(a+b)] Не найдено: 33 | Нужно включить: 33

Click here 👆 to get an answer to your question ✍️ The coefficient of x in the expansion of (x+3)^3 is Select one: a. 6 b. 27 c. I d 9.