19 авг. 2013 г. · If n has a factor of 2 but no factor of 3, then 8n has the same number of distinct prime factors as n, and 9n has one more, namely, 3. |
2 июн. 2013 г. · For example we can show that around 12.6% of 10,000 digit numbers are constructed from 10 distinct prime numbers and around 68% (±σ) are ... |
27 янв. 2016 г. · The Hardy–Ramanujan theorem says that the number of distinct prime factors of n has normal order loglogn... i.e., most numbers have about ... |
19 сент. 2014 г. · I want to prove that if ω(n) is the number of distinct prime factors of n for n>2 we have ω(n)≤lnnlnlnn+O(lnn(lnlnn)2). How can I do this? |
3 авг. 2021 г. · Positive odd numbers with two prime factors are: 9, 15, 21, 25, 33, 35, ... (A046315); Positive odd numbers with three prime factors are: 27, 45 ... |
19 дек. 2018 г. · So all you need is to multiply all primes until you reach 264. Share. |
2 апр. 2015 г. · The standard definition of ω(n) is the number of distinct prime divisors of n; see here. Note also that it must be distinct instead of with multiplicity. |
1 февр. 2023 г. · What I actually meant is the number of "distinct prime power factors" of φ(n) in the following sense: Statement: Let n=p1…pk ... |
6 февр. 2022 г. · The maximum number k of distinct prime factors of a number m≤n is attained when m is the product of the first k primes. |
11 окт. 2015 г. · Number of distinct prime factors of an+bn+cn · 0 · Find a closed form for the number of divisors of m that are relatively prime to n · 0. |
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