the slope of plot between ln kvs 1 t gives - Axtarish в Google
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9 янв. 2020 г. · This is an equation of line with ln k on y-aris I/T on x -axis and slope = − E a / R So, option A is the correct answer.
12 сент. 2021 г. · NEET 2021: The slope of Arrhenius Plot ( ln k v / s (1/ T )) of first order reaction is -5 × 103 K. The value of E a of the reaction is.
3 июл. 2022 г. · The slope of Arrhenius Plot (ln k v/s 1T) of first order reaction is –5×103 K. The value of Ea of the reaction is. Choose the correct option ...
2 мая 2024 г. · When a graph is plotted between lnk v/s 1 T , it gives a straight line with slope m = − E a R . So, the Arrhenius plot is a graph between ln k ...
13 сент. 2021 г. · The slope of Arrhenius Plot (In k v/s1T) ( In k v/s 1 T ) of first order reaction is –5 × 103 K. The value of Ea of the reaction is. Choose the ...
The slope of Arrhenius plot (lnk vs 1/T) of a first order reaction is −5×103. The value of Ea of the reaction is (R=8.314JK−1mol−1). A. 83.0kJmol−1.
23 мая 2024 г. · From this equation, a plot of ln k versus 1/T will yield a straight line with a slope of -Ea/R. Therefore, the correct option is B.
The correct Answer is:D. d) Plot of In k vs 1/T gives. Slope = −EaR −1×104=−EaR Ea=R×(1×104) =8.314×104Jmol−1=83.14×103Jmol−1 =83.14kJmol−1.
When ln k is plotted against 1/T, the slope was found to be -10.7 × 103 K, activation energy for the reaction would be : -78.9 kJ mol−1. 2.26 kJ mol−1. Не найдено: kvs | Нужно включить: kvs
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