26 апр. 2016 г. · I see two ways in which the thermal de Broglie wavelength is defined. In both cases we can get it from the probability distribution and ...

27 авг. 2016 г. · Factor π in thermal de Broglie wavelength ... one derives this with λ=hp, E=p22m and E=π⋅kBT. What is the meaning of π in the expression for the ...

14 апр. 2022 г. · The de Broglie wavelength is a very rough measure of the "size" of a particle, and this can be rather different for electrons and holes due to ...

10 окт. 2014 г. · I'm curious where the de Broglie relation p=hλ comes from? ... But how is the expression p=hλ obtained for a massive particle where E≠pc?

19 мар. 2016 г. · I'm stuck with derivation of critical temperature and thermal wavelength for Bose-Einstein condensate - all sources describe equations very briefly.

19 авг. 2015 г. · In the derivation of the Thermal De Broglie Wavelength on Wikipedia, I come across the following: "In the nonrelativistic case the effective ...

28 июн. 2022 г. · While deriving blackbody radiation, we assume that a standing wave of a particular wavelength can have energy E=nhν, where ν is the frequency ...

7 мая 2015 г. · The thermal de Broglie wavelength indicitates roughly when you have to treat a gas clasically or quantum mechanically.

21 мар. 2018 г. · Thinking about this answer: KE(rel)=(γ−1)mc2. Thus, if T=KE(rel): γ=1+T/mc2. If T>>2mc2>mc2: γ≈T/mc2. By the other hand, from the de Broglie ... Не найдено: thermal | Нужно включить: thermal

13 апр. 2023 г. · This can be done using the Boltzmann factor and integrating over phase space. where λ=√2πℏ2kBTm is the thermal de Broglie wavelength of the ...