27 янв. 2018 г. · The volume of the shell is approximately, the surface area of the shell multiplied by the thickness of the shell.

16 июн. 2016 г. · Let's forget about “infinitesimal” quantities and just look at the difference that you've computed: V(r+h)=V(r)+4πr2h+4πrh2+43πh3.

30 июл. 2016 г. · The volume of the shell is 4πr20Δr. You can think at a solid with base surface the sphere and ''height'' Δr. Or you can calculate the volume ...

11 авг. 2017 г. · it follows that the volume of the sphere is V=∫baπ[f(x)]2dx=∫r−rπ(r2−x2)dx=π[r2x−x33]=43πr3.

2 сент. 2020 г. · First thing, the volume must be r3V1, where V1 is the volume of a unit sphere. – user1353692. Commented Oct 1 at 9:13.

19 июл. 2015 г. · The exact formula V=(4/3)πR3 can be obtained using power sums (see Dr. MV's answer (Method 1) and my own answer). A.G. referred to the multiple ...

28 апр. 2014 г. · I'm looking to calculate the outer radius of a spherical shell of a desired volume and thickness. I don't know if the years have knocked some obvious obstacle ...

4 дек. 2018 г. · In order for the 'thickened' sphere to have double the volume of the original one, its radius must be 3√2 times as big as the original, as the ...

7 окт. 2015 г. · I was trying to find the volume of concentrical sphere shells but to my surprise i come up with equal volume when evidently the outer shell should have more ...

23 янв. 2021 г. · To find volume using cylindrical shell method, please take shells along the axis of the cylinder. At any given radius, −√4b ...