28 мая 2020 г. · The correct formula is V = (4/3)*pi*R^3. The derivative of volume with respect to radius is the surface area: dV/dr = 4*pi*R^2 ... If the radius of a sphere is increasing at 2 cm/s, find the rate of ... What is the rate of change of the volume of a sphere ... - Quora What is the change in the volume of a sphere if you increase ... Другие результаты с сайта www.quora.com

9 янв. 2020 г. · Rate of change of Volume of a sphere with respect to its surface area, when the radius is 2 cm is 1 c m 3 / c m 2 . Was this answer helpful?

21 нояб. 2018 г. · How Fast is the Volume Changing with Respect to the Radius When the Radius is 2 Cm ... The radius of a sphere is changing at the rate of 0.1 cm/ ...

d V d A = 1 2 16 π + 16 π 4 16 π. Simplify to get the rate of change of volume with respect to surface area when the radius is 2 cm: d V d A = 2 π + π 2.

7 авг. 2024 г. · Thus, the rate of change of the volume of the ball with respect to its radius when the radius is 2 cm is: dVdr=16π cm3/cm.

7 авг. 2024 г. · Thus, the rate of change of volume with respect to surface area when the radius is 2 cm is: dVdS=1 cm3/cm2.

27 мар. 2015 г. · Firs evaluate the derivative of your volume (with respect to r : V'(r)=dV(r)dr=(43)π⋅3r2. Now substitute r=5 in it: V'(5)=(43)π⋅3⋅25=100π.

Volume of a sphere, V=43πr3. Given, rate of change of radius, drdt=2 cm/s and radius, r=10 cm. Rate of change of volume is given by dVdt

8 дек. 2015 г. · Notice, volume of the sphere is given as V=4π3r3. differentiating volume V w.r.t. time t as follows dVdt=43π(3r2drdt)=4πr2drdt. How can rate of change be with respect to time if you're not ... Instantaneous rates of change - Mathematics Stack Exchange Instantaneous rate of change of the volume of a cone with ... How do I find the instantaneous rate of change of the volume of ... Другие результаты с сайта math.stackexchange.com

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Опубликовано: 8 окт. 2019 г.