what is the remainder when 3^24 is divided by 5 site:gmatclub.com - Axtarish в Google
8 июн. 2016 г. · 3^24 will have "1" in units digit. Thus, 1/5 => Remainder is 1. This concept may help when the power is a bigger number.
21 окт. 2012 г. · Since 243=240+3=(multiple of 4)+3, then the remained upon division of 3^243 by 5 will be the third number in the pattern, which is 2.
11 дек. 2019 г. · Since 5 x 2=10 and 3*3=9, every 9 on division with 5 shall give a remainder of -1. 35 on division with 2 gives 17 as quotient and 1 as remainder ...
27 апр. 2016 г. · 123: 4 = 30 with remainder of 3. 3^3 will have the unit digit of 7, thereby dividing by 5 will leave a remainder of 2. C. Simple and straight to the point!
15 окт. 2020 г. · 24*38= The unit digit is 2. 17^7= The unit digit is 3. Therefore 3+2=5 and when 5 is divided by 3 the remainder is 2.
12 дек. 2019 г. · (3^283)/5 = (3*(3^2)^141)/5= (3*(10-1)^141)/5 = 3*(-1/5) = -3/5 hence remainder = -3+5 = 2 The answer
15 апр. 2016 г. · Let n=5 (leaves a remainder of 5 when divided by 24) 3n = 3(5) =15, which leaves a remainder of 7 when divided by 8. Answer E
11 мая 2022 г. · What is the remainder when 24^3*38^5 is divided by 3 ? A. 0 B. 1 C. 2 D. 3 E. Cannot be calculated.
15 февр. 2017 г. · The last digit of 2^24 will be same as last digit of 2^4 which is 6. Hence, when divided by 5 the remainder will be 1.
21 июл. 2015 г. · When n is divided by 5 the remainder is 3. What is the remainder when (n + 4)^2 is divided by 5? A. 0 B. 1 C. 2 D. 3 E. 4 Kudos for a ...
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