15 мар. 2013 г. · How can a global script variable be passed to the command of xargs? I tried it this way: TEST=hallo2 echo "hallo" | xargs sh -c 'echo passed=$1 test=$TEST' sh

6 дек. 2019 г. · Assign value to a variable in shell script is like below a=$(echo $1 | xargs file). The above means that execute what is inside $(.

25 июн. 2018 г. · I am looking for a way to set a variable in the statements passed to xargs. The value is to be manipulated in one of the commands.

23 янв. 2024 г. · I'm running into strange behavior with xargs in a bash script where the replacement is not working anymore when placing it in the middle of a variable with ...

18 окт. 2017 г. · The solution: -I -I lets you name your argument and put it anywhere you like. Eg ls | xargs -n 1 -I {} echo prefix_{} (replace {} with any string)

23 мар. 2016 г. · I am trying to run many commands in parallel, and need to do some string manipulation on the input first. How can I make the below example work?

28 нояб. 2013 г. · I want to do something similar to this: find . -type f | xargs cp dest_dir But xargs will use dest_dir as initial argument, not as final argument.

4 февр. 2021 г. · xargs crams as many arguments into each command as possible. It does not matter whether those arguments are in the same line or in different lines.

19 окт. 2016 г. · Apparently xargs splits the input line on whitespace when the -I option is not used, but with -I it treats the line as one argument.

22 мар. 2020 г. · The intention of the xargs command is to substitute the string X with the argument, not to define the shell variable $X.